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　　AI進(jìn)??(jin)行??(xing)預(yù)?(yu)測??(ce)的??(de)邏??(luo)輯??(ji)基??(ji)礎(chǔ)??(chu)是??(shi)統(tǒng)??(tong)計??(ji)學(xué)??(xue)、機(jī)?(ji)器??(qi)學(xué)??(xue)習(xí)??(xi)和??(he)數(shù)??(shu)據(jù)?(ju)挖??(wa)掘??(jue)?，通??(tong)過??(guo)分??(fen)析?(xi)歷?(li)史??(shi)數(shù)??(shu)據(jù)??(ju)中??(zhong)的??(de)模??(mo)式??(shi)和??(he)規(guī)??(gui)律??(lv)?，推??(tui)斷??(duan)未??(wei)來??(lai)事?(shi)件??(jian)或??(huo)結(jié)??(jie)果??(guo)的??(de)可??(ke)能??(neng)性??(xing)??。??但??(dan)是??(shi)?，彩??(cai)票??(piao)每??(mei)次??(ci)開??(kai)獎??(jiang)具??(ju)有??(you)隨??(sui)機(jī)??(ji)性?(xing)和??(he)獨(dú)??(du)立??(li)性??(xing)?，往?(wang)期??(qi)開??(kai)獎??(jiang)數(shù)??(shu)據(jù)??(ju)與??(yu)未??(wei)來??(lai)開??(kai)獎??(jiang)結(jié)??(jie)果??(guo)之??(zhi)間??(jian)沒??(mei)有??(you)關(guān)??(guan)系??(xi)?，即??(ji)使??(shi)AI能??(neng)對??(dui)歷??(li)史??(shi)開??(kai)獎??(jiang)號??(hao)碼??(ma)進(jìn)??(jin)行??(xing)所??(suo)謂??(wei)的??(de)“復(fù)??(fu)雜??(za)”分??(fen)析??(xi)?，也??(ye)無??(wu)法??(fa)預(yù)?(yu)測??(ce)下??(xia)一??(yi)次??(ci)開??(kai)獎?(jiang)號??(hao)碼??(ma)?，因??(yin)為??(wei)彩??(cai)票??(piao)的??(de)每??(mei)次?(ci)開??(kai)獎??(jiang)都??(dou)是??(shi)獨(dú)??(du)立??(li)事?(shi)件??(jian)?，不??(bu)受??(shou)之??(zhi)前??(qian)結(jié)?(jie)果??(guo)的??(de)影??(ying)響??(xiang)??。那??(na)些祝(xie)聲??(sheng)稱??(cheng)用??(yong)AI能??(neng)預(yù)??(yu)測??(ce)中??(zhong)獎??(jiang)號??(hao)碼祝(ma)的??(de)不??(bu)法??(fa)分??(fen)子??(zi)?，只??(zhi)不?(bu)過??(guo)是??(shi)利??(li)用??(yong)了??(le)人??(ren)們??(men)渴??(ke)望??(wang)中??(zhong)獎??(jiang)的??(de)心??(xin)理??(li)?，編??(bian)造?(zao)了??(le)一??(yi)個??(ge)看??(kan)似??(si)“科??(ke)學(xué)??(xue)”的??(de)騙??(pian)局??(ju)???！　〔??(cai)票??(piao)是??(shi)一??(yi)種?(zhong)概??(gai)率??(lv)游??(you)戲??(xi)??，以??(yi)雙??(shuang)色??(se)球??(qiu)為??(wei)例?(li)??，按??(an)照??(zhao)游??(you)戲??(xi)規(guī)??(gui)則?(ze)??，從??(cong)1-33個??(ge)紅??(hong)色??(se)球?(qiu)號??(hao)碼??(ma)中??(zhong)選??(xuan)擇??(ze)6個??(ge)、從??(cong)1-16個??(ge)藍(lán)??(lan)色??(se)球??(qiu)號??(hao)碼??(ma)中??(zhong)選??(xuan)擇??(ze)1個??(ge)組??(zu)成??(cheng)1注??(zhu)號??(hao)碼??(ma)??。??而??(er)這??(zhe)樣??(yang)的??(de)組??(zu)合??(he)數(shù)??(shu)有??(you)1772萬??(wan)多??(duo)種??(zhong)??，每??(mei)一??(yi)種??(zhong)組??(zu)合?(he)有??(you)著??(zhe)相??(xiang)同??(tong)的??(de)中?(zhong)獎??(jiang)概??(gai)率??(lv)??。并??(bing)且??(qie)??，每??(mei)次??(ci)開??(kai)獎??(jiang)都??(dou)是??(shi)一??(yi)次??(ci)獨(dú)??(du)立??(li)的?(de)隨??(sui)機(jī)??(ji)事?(shi)件??(jian)??，毫??(hao)無??(wu)規(guī)?(gui)律??(lv)可??(ke)言??(yan)??。。