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學習快評丨qibao666888　　他??(ta)認?(ren)為?(wei)??，AI有??(you)望??(wang)助??(zhu)力??(li)解??(jie)決??(jue)科??(ke)學??(xue)研??(yan)究??(jiu)過??(guo)程??(cheng)中??(zhong)人??(ren)類?(lei)科??(ke)學??(xue)家??(jia)面??(mian)臨??(lin)的??(de)問??(wen)題??(ti)??。??AI4S將??(jiang)逐??(zhu)步??(bu)從??(cong)通??(tong)用??(yong)大??(da)模??(mo)型??(xing)的??(de)簡?(jian)單??(dan)應??(ying)用??(yong)向??(xiang)大??(da)模??(mo)型??(xing)特??(te)定??(ding)學??(xue)科?(ke)垂??(chui)域??(yu)化??(hua)應??(ying)用??(yong)、面??(mian)向??(xiang)特??(te)定??(ding)數??(shu)據??(ju)和?(he)科??(ke)學??(xue)任??(ren)務??(wu)的??(de)AI設??(she)計??(ji)、面??(mian)向??(xiang)非??(fei)自??(zi)然??(ran)語??(yu)言??(yan)類??(lei)科??(ke)學??(xue)大??(da)數??(shu)據??(ju)的??(de)AI設??(she)計??(ji)直??(zhi)至??(zhi)AI主??(zhu)導??(dao)的??(de)科??(ke)研??(yan)全??(quan)流?(liu)程??(cheng)增??(zeng)強??(qiang)等??(deng)方??(fang)向??(xiang)逐??(zhu)步?(bu)深??(shen)入??(ru)???！　≈??(zhong)新??(xin)網??(wang)北??(bei)京??(jing)3月??(yue)25日?(ri)電??(dian) (記??(ji)者??(zhe) 孫??(sun)自??(zi)法??(fa))“人??(ren)有??(you)人??(ren)智??(zhi)??，機??(ji)有??(you)機?(ji)‘智?(zhi)’??，今??(jin)后?(hou)要??(yao)爭?(zheng)取?(qu)做??(zuo)到??(dao)人??(ren)類??(lei)和?(he)人??(ren)工??(gong)智??(zhi)能??(neng)‘各??(ge)顯??(xian)其??(qi)智??(zhi)??，智??(zhi)智?(zhi)與??(yu)共??(gong)’”“人??(ren)工??(gong)智??(zhi)能??(neng)是?(shi)腦??(nao)的??(de)數??(shu)字??(zi)孿??(luan)生??(sheng)”“人??(ren)工??(gong)智??(zhi)能??(neng)+機?(ji)器??(qi)自??(zi)動??(dong)化??(hua)是??(shi)未??(wei)來?(lai)發(fā)??(fa)展??(zhan)的??(de)必??(bi)然??(ran)趨??(qu)勢??(shi)”“人??(ren)工??(gong)智??(zhi)能??(neng)賦??(fu)能?(neng)科??(ke)學??(xue)家?(jia)的??(de)最??(zui)佳??(jia)模??(mo)式??(shi)是??(shi)人??(ren)機??(ji)協(xié)??(xie)同??(tong)、人?(ren)智??(zhi)協(xié)??(xie)同??(tong)”……。