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學習快評丨qibao666888　　彩??(cai)票??(piao)是??(shi)一??(yi)種??(zhong)概??(gai)率?(lv)游??(you)戲??(xi)??，以?(yi)雙??(shuang)色??(se)球??(qiu)為??(wei)例??(li)??，按??(an)照??(zhao)游??(you)戲?(xi)規(guī)??(gui)則??(ze)??，從?(cong)1-33個??(ge)紅??(hong)色??(se)球??(qiu)號??(hao)碼??(ma)中??(zhong)選??(xuan)擇??(ze)6個??(ge)、從??(cong)1-16個??(ge)藍??(lan)色??(se)球?(qiu)號??(hao)碼??(ma)中??(zhong)選??(xuan)擇?(ze)1個??(ge)組??(zu)成??(cheng)1注??(zhu)號??(hao)碼??(ma)??。??而??(er)這?(zhe)樣??(yang)的??(de)組??(zu)合?(he)數(shù)??(shu)有?(you)1772萬??(wan)多??(duo)種??(zhong)??，每?(mei)一??(yi)種??(zhong)組??(zu)合??(he)有祝(you)著??(zhe)相??(xiang)同??(tong)的??(de)中??(zhong)獎??(jiang)概??(gai)率??(lv)??。并??(bing)且??(qie)??，每??(mei)次??(ci)開??(kai)獎?(jiang)都??(dou)是??(shi)一??(yi)次??(ci)獨??(du)立??(li)的??(de)隨??(sui)機??(ji)事??(shi)件??(jian)??，毫??(hao)無??(wu)規(guī)??(gui)律??(lv)可??(ke)言??(yan)???！　I進??(jin)行??(xing)預??(yu)測??(ce)的??(de)邏??(luo)輯??(ji)基??(ji)礎??(chu)是?(shi)統(tǒng)??(tong)計??(ji)學??(xue)、機??(ji)器?(qi)學??(xue)習??(xi)和??(he)數(shù)??(shu)據(jù)??(ju)挖??(wa)掘??(jue)?，通??(tong)過??(guo)分??(fen)析??(xi)歷??(li)史??(shi)數(shù)??(shu)據(jù)??(ju)中??(zhong)的??(de)模??(mo)式??(shi)和??(he)規(guī)??(gui)律??(lv)?，推?(tui)斷?(duan)未??(wei)來??(lai)事??(shi)件??(jian)或??(huo)結(jié)??(jie)果??(guo)的??(de)可??(ke)能??(neng)性??(xing)??。??但??(dan)是??(shi)?，彩??(cai)票??(piao)每??(mei)次??(ci)開??(kai)獎??(jiang)具??(ju)有??(you)隨??(sui)機??(ji)性??(xing)和??(he)獨??(du)立??(li)性??(xing)?，往??(wang)期??(qi)開??(kai)獎??(jiang)數(shù)??(shu)據(jù)??(ju)與?(yu)未??(wei)來??(lai)開??(kai)獎??(jiang)結(jié)??(jie)果??(guo)之??(zhi)間??(jian)沒?(mei)有??(you)關(guān)??(guan)系??(xi)?，即??(ji)使??(shi)AI能??(neng)對??(dui)歷??(li)史??(shi)開??(kai)獎??(jiang)號??(hao)碼??(ma)進??(jin)行??(xing)所??(suo)謂??(wei)的??(de)“復??(fu)雜??(za)”分??(fen)析??(xi)?，也??(ye)無??(wu)法??(fa)預??(yu)測??(ce)下??(xia)一??(yi)次??(ci)開??(kai)獎??(jiang)號??(hao)碼??(ma)?，因??(yin)為??(wei)彩??(cai)票??(piao)的??(de)每??(mei)次??(ci)開??(kai)獎??(jiang)都??(dou)是??(shi)獨?(du)立??(li)事??(shi)件??(jian)?，不??(bu)受??(shou)之??(zhi)前??(qian)結(jié)??(jie)果??(guo)的??(de)影?(ying)響??(xiang)??。那?(na)些??(xie)聲??(sheng)稱??(cheng)用??(yong)AI能??(neng)預??(yu)測??(ce)中??(zhong)獎??(jiang)號??(hao)碼??(ma)的??(de)不??(bu)法??(fa)分??(fen)子??(zi)?，只??(zhi)不??(bu)過??(guo)是??(shi)利??(li)用??(yong)了??(le)人??(ren)們??(men)渴??(ke)望??(wang)中??(zhong)獎??(jiang)的??(de)心??(xin)理??(li)?，編??(bian)造??(zao)了??(le)一??(yi)個??(ge)看??(kan)似??(si)“科??(ke)學??(xue)”的??(de)騙??(pian)局??(ju)??。。